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Self powers

Problem 48 Published on Friday, 18th July 2003, 06:00 pm; Solved by 92548;
Difficulty rating: 5%

The series, 11 + 22 + 33 + ... + 1010 = 10405071317.

Find the last ten digits of the series, 11 + 22 + 33 + ... + 10001000.