## Self powers

### Problem 48

The series, 1^{1} + 2^{2} + 3^{3} + ... + 10^{10} = 10405071317.

Find the last ten digits of the series, 1^{1} + 2^{2} + 3^{3} + ... + 1000^{1000}.

The series, 1^{1} + 2^{2} + 3^{3} + ... + 10^{10} = 10405071317.

Find the last ten digits of the series, 1^{1} + 2^{2} + 3^{3} + ... + 1000^{1000}.