## Totient Chains

### Problem 214

Published on Saturday, 25th October 2008, 02:00 pm; Solved by 3364Let φ be Euler's totient function, i.e. for a natural number `n`,
φ(`n`) is the number of `k`, 1 ≤ `k` ≤ `n`, for which gcd(`k`,`n`) = 1.

By iterating φ, each positive integer generates a decreasing chain of numbers ending in 1.

E.g. if we start with 5 the sequence 5,4,2,1 is generated.

Here is a listing of all chains with length 4:

5,4,2,1

7,6,2,1

8,4,2,1

9,6,2,1

10,4,2,1

12,4,2,1

14,6,2,1

18,6,2,1

7,6,2,1

8,4,2,1

9,6,2,1

10,4,2,1

12,4,2,1

14,6,2,1

18,6,2,1

Only two of these chains start with a prime, their sum is 12.

What is the sum of all primes less than 40000000 which generate a chain of length 25?