## Number Rotations

### Problem 168

Published on Friday, 16th November 2007, 05:00 pm; Solved by 1491Consider the number 142857. We can right-rotate this number by moving the last digit (7) to the front of it, giving us 714285.

It can be verified that 714285=5×142857.

This demonstrates an unusual property of 142857: it is a divisor of its right-rotation.

Find the last 5 digits of the sum of all integers `n`, 10 < `n` < 10^{100}, that have this property.