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Diophantine reciprocals II

Problem 110

Published on 02 December 2005 at 06:00 pm [Server Time]

In the following equation x, y, and n are positive integers.

1

x
+
1

y
=
1

n

It can be verified that when n = 1260 there are 113 distinct solutions and this is the least value of n for which the total number of distinct solutions exceeds one hundred.

What is the least value of n for which the number of distinct solutions exceeds four million?

NOTE: This problem is a much more difficult version of Problem 108 and as it is well beyond the limitations of a brute force approach it requires a clever implementation.


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